The product ID/key for MS SQL is located in registry and is in unreadable format (binary I guess). Anyway, I found the script from HERE and would like to share with you guys. Works like charm and also it worth to mention that it DOESNT work on SQL 2005. :(
1. Copy below script
function Get-SQLserverKey {
## function to retrieve the license key of a SQL 2008 Server.
param ($targets = ".")
$hklm = 2147483650
$regPath = "SOFTWARE\Microsoft\Microsoft SQL Server\100\Tools\Setup"
$regValue1 = "DigitalProductId"
$regValue2 = "PatchLevel"
$regValue3 = "Edition"
Foreach ($target in $targets) {
$productKey = $null
$win32os = $null
$wmi = [WMIClass]"\\$target\root\default:stdRegProv"
$data = $wmi.GetBinaryValue($hklm,$regPath,$regValue1)
[string]$SQLver = $wmi.GetstringValue($hklm,$regPath,$regValue2).svalue
[string]$SQLedition = $wmi.GetstringValue($hklm,$regPath,$regValue3).svalue
$binArray = ($data.uValue)[52..66]
$charsArray = "B","C","D","F","G","H","J","K","M","P","Q","R","T","V","W","X","Y","2","3","4","6","7","8","9"
## decrypt base24 encoded binary data
For ($i = 24; $i -ge 0; $i--) {
$k = 0
For ($j = 14; $j -ge 0; $j--) {
$k = $k * 256 -bxor $binArray[$j]
$binArray[$j] = [math]::truncate($k / 24)
$k = $k % 24
}
$productKey = $charsArray[$k] + $productKey
If (($i % 5 -eq 0) -and ($i -ne 0)) {
$productKey = "-" + $productKey
}
}
$win32os = Get-WmiObject Win32_OperatingSystem -computer $target
$obj = New-Object Object
$obj | Add-Member Noteproperty Computer -value $target
$obj | Add-Member Noteproperty OSCaption -value $win32os.Caption
$obj | Add-Member Noteproperty OSArch -value $win32os.OSArchitecture
$obj | Add-Member Noteproperty SQLver -value $SQLver
$obj | Add-Member Noteproperty SQLedition -value $SQLedition
$obj | Add-Member Noteproperty ProductKey -value $productkey
$obj
}
}
2. Open up windows powershell
3. Rightclick in the powershell window. It should paste above code, otherwise select paste
4. Type in: "Get-SQLserverKey". Press enter. In certain cases you may need to press enter twice, or thrice
If you get error null exception, that means that you didnt have any MSSQL installed OR yours is evaluation version.
Updated 15/3/2016
For SQL 2012, please use below script.It has some minor changes as previous script won't work on 2012.
function GetSqlServerProductKey {
## function to retrieve the license key of a SQL 2008 Server.
param ($targets = ".")
$hklm = 2147483650
$regPath = "SOFTWARE\Microsoft\Microsoft SQL Server\110\Tools\Setup"
$regValue1 = "DigitalProductId"
$regValue2 = "PatchLevel"
$regValue3 = "Edition"
Foreach ($target in $targets) {
$productKey = $null
$win32os = $null
$wmi = [WMIClass]"\\$target\root\default:stdRegProv"
$data = $wmi.GetBinaryValue($hklm,$regPath,$regValue1)
[string]$SQLver = $wmi.GetstringValue($hklm,$regPath,$regValue2).svalue
[string]$SQLedition = $wmi.GetstringValue($hklm,$regPath,$regValue3).svalue
$binArray = ($data.uValue)[0..16]
$charsArray = "B","C","D","F","G","H","J","K","M","P","Q","R","T","V","W","X","Y","2","3","4","6","7","8","9"
## decrypt base24 encoded binary data
For ($i = 24; $i -ge 0; $i--) {
$k = 0
For ($j = 14; $j -ge 0; $j--) {
$k = $k * 256 -bxor $binArray[$j]
$binArray[$j] = [math]::truncate($k / 24)
$k = $k % 24
}
$productKey = $charsArray[$k] + $productKey
If (($i % 5 -eq 0) -and ($i -ne 0)) {
$productKey = "-" + $productKey
}
}
$win32os = Get-WmiObject Win32_OperatingSystem -computer $target
$obj = New-Object Object
$obj | Add-Member Noteproperty Computer -value $target
$obj | Add-Member Noteproperty OSCaption -value $win32os.Caption
$obj | Add-Member Noteproperty OSArch -value $win32os.OSArchitecture
$obj | Add-Member Noteproperty SQLver -value $SQLver
$obj | Add-Member Noteproperty SQLedition -value $SQLedition
$obj | Add-Member Noteproperty ProductKey -value $productkey
$obj
}
}
